Pressure booster

Technical data

Operation notes If the outlet capacity is undersized, pulsation may occur Make sure to install a mist separator at the inlet side of the booster regulator, supply air must be dry - non lubricated The booster regulator has a sliding part inside, and it generates dust. Also, install a cleaning device such as an air filter or a mist separator on the outlet side as necessary Depending on the necessity, install a silencer on the exhaust port of the booster regulator to reduce the exhaustion sound Provide a dedicated pipe to release the exhaust air from each booster regulator. If exhaust air is converged into a pipe, the back pressure that is created could cause improper operation

Connection to the compressed air network and functions

In case of direct connection of the booster to the system, a 3/2 valve (6) should be used to open and close the circuit at the output of the multiplier. An air filter should also be included at the output, as the booster contains moving parts. A filter should be included at the input to separate water and mist from the air, the air must not be lubricated. The booster provides high-pressure air in a “pulsating” manner, therefore it is recommended to use an air tank (4) at the output of the booster to avoid pulsation during use. To speed up the initiation/filling of the system, it is recommended to connect a one-way check valve, as shown in figure (5). The selection of a pressure booster does not only include the compression ratio, but above all a sufficient volume of the air tank to ensure the correct supply of the consumers. First, it is necessary to calculate the volume of air taken by the consumers (cylinders, blowing nozzles, etc.), and then determine the corresponding volume of the air tank. Silencers must be installed on the operating exhausts (not included). The booster is activated automatically as soon as the inlet pressure (p1) is applied and operates until the outlet pressure (p2) reaches twice the inlet pressure (at a compression ratio of 1:2) or three times (at a ratio of 1:3). The booster is not designed for free exhaust operation, but always requires a connected application. The outlet pressure can be regulated using a pressure regulator if necessary. If no air is being extracted at the outlet, the integrated check valves allow the increased pressure to be maintained even if the inlet pressure is removed.

Example of circuit usage

In factories where only specific equipment requires high pressure, a booster cylinder can be installed in the corresponding local air circuit. This allows the overall air circuit to maintain low pressure while enabling the use of highpressure equipment in localized areas. This design not only reduces the pressure demand on the overall air circuit but also effectively saves energy and decreases the load on the equipment.

When using two booster cylinders for two-stage boosting, ensure that each booster cylinder is supplied with sufficient airflow to maintain the stability of the inlet pressure at the booster valve. This is critical for ensuring the stability and efficiency of the boosting process.

During the process of charging the air tank, a circuit design incorporating a booster cylinder in parallel with a check valve is used. When the pressure in the air tank is lower than the inlet air source pressure, the air source directly charges the tank through the check valve. This method efficiently utilizes the air source pressure, reducing the charging time and improving overall efficiency.

The inlet pressure (P₁) first passes through a check valve to charge P₂, until P₁ = P₂

When the actuator's output force is insufficient and spatial constraints prevent the use of a larger cylinder, a booster cylinder can be employed to increase output force without replacing the existing actuator.
In cases where miniaturization of the drive component is required, and a small cylinder size is needed while maintaining a high output force, a booster cylinder offers an effective solution.

For single-acting cylinder operations, installing a booster cylinder in the corresponding air supply circuit can reduce compressed air consumption, achieving more efficient operation.

Charakteristiky

Calculation of the filling time of a tank

Example of calculating the filling time of a tank with a volume of 50 liters when increasing the pressure from the starting pressure of 0,7 MPa to the final pressure of 0,9 MPa using the pressure amplifier PBS00106312 with an input pressure of 5 bar. Values for the calculation: input pressure: P1 = 0,5 MPa, initial pressure in the tank: STP = 0,7 MPa, final pressure in the tank: FTP = 0,9 MPa, tank volume: V = 50 l. We calculate the ratio STP/ P1 and FTP/P1, i.e. 0,7/0,5=1,4 and 0,9/0,5=1,8. From the graph, we determine the time values corresponding to the specified pressure ratios, i.e. for P2/P1=1,4 it is a value of approximately 2,5 s, for a ratio of 1.8 it is a value of 8,5 s. We subtract the values, i.e. 8,5-2,5=6 s. The pressurization time of 10 l to a pressure of 0,9 MPa under the specified conditions is 6 s. Pressurization of 50 l will therefore be a multiple of 6 x 5=30 s.